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4(-4x^2-5x+2)+5(4x^2-3x-5)=0
We multiply parentheses
-16x^2+20x^2-20x-15x+8-25=0
We add all the numbers together, and all the variables
4x^2-35x-17=0
a = 4; b = -35; c = -17;
Δ = b2-4ac
Δ = -352-4·4·(-17)
Δ = 1497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1497}}{2*4}=\frac{35-\sqrt{1497}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1497}}{2*4}=\frac{35+\sqrt{1497}}{8} $
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